Current location - Training Enrollment Network - Mathematics courses - Weibo's Mathematical Answers
Weibo's Mathematical Answers
Let the soldiers speed x and the team speed y.

The first process: soldiers walk from the end of the platoon to the head of the platoon.

The speed of the soldiers relative to the team is (x-y), and they left 100m, so the soldiers spent 100/(x-y) in this process.

The second process: soldiers walk from the front row to the back row.

The speed of the soldiers relative to the team is (x+y), and they also walk 100m, and the time is 100/(x+y).

So the total time spent by soldiers is100/(x-y)+100/(x+y).

The team went straight ahead at the same speed and walked 100 meters, so the total time of the team was100/y.

The two total times are the same, and the equation is:

100/(x-y)+ 100/(x+y)= 100/y

Multiply both sides by (x-y) (x+y) y:

X * x-2xy-y * y = 0 (the square of y is difficult to express, so y * y is used to express the square of y).

Solve this equation to get the relationship between y and x: y = 1 root number 2. (The root number is not easy to type, which is indicated by the Chinese character root number 2)

Take the sign and the root number 2 = 1.4 14 to get y = 2.4 14x.

The team walked 100 meters at the speed of X in the total time, so the soldiers must have walked 24 1.4 meters at the speed of Y in the same time.