2. The length is 2. BC: (open 2)/2.
Distance 2 = AB 2-( 1/2bc) 2
Therefore, the root of the distance ={ 1-[ (root 2)/4] 2} =(7/8).
3.AB^2+AC^2=BC^2 ( 1)
Distance from b to surface a L 1=AB*sin30 degrees (2)
C...L2 = AC * sine 45 degrees (3)
If we want to discuss the distance from BC to plane A, BC is parallel to plane A..
L 1=L2= distance (4)
Substitute (2), (3) and (4) into (1) to get the solution.
Square root of distance =6
("Plane B" should be changed to "Plane A")
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