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Division with remainder in grade two.
The skills of division with remainder in grade two are as follows:

The purpose of division is to find the quotient, but when you suddenly can't see how many quotients are contained in the dividend, you can use the method of trial quotient and estimated quotient to see how many divisors are contained in the highest digit of the multiplicand (that is, how many times the quotient is contained), and then add several times the complement from the standard number to get the quotient.

Small array: When the dividend contains divisor 1, 2, 3 times, the period method is:

Dividend includes quotient 1 multiple: the complement is added once from the standard.

Dividends include two quotients: from standard to supplementary.

Dividends include three quotients: from standard to supplementary three times.

Multi-digit division law:

(1) Divide from the high order of the dividend, and look at the first few digits of the dividend. If it is not enough, look at one more digit.

(2) Write the quotient on the divisor. If the divisor is not enough, put the quotient 0 on it.

(3) The remainder of each division must be less than the divisor. Place the digits of the divisor in the right of the remainder and continue the division.

In division with remainder, the remainder must be less than the divisor. In the division formula, dividend-divisor = quotient ... remainder, where the remainder must be less than divisor. Assuming that the remainder is greater than the divisor and the quotient is not the largest, then the remainder must be less than the divisor in the division with remainder.

In the division formula with residue, the residue is 3, the minimum residue is 4, the divisor is 3, the maximum residue is 2, the residue is 3, the minimum residue is 3+ 1=4, the divisor is 3, and the maximum residue is 3-1= 2; So the answer is 4.