Current location - Training Enrollment Network - Mathematics courses - Math problems in the sixth grade
Math problems in the sixth grade
1, the radius of the cylinder bottom is 3cm, and the height is 6.5cm. What is the surface area?

Solution: Surface area = lateral area +2 bottom area.

Transverse area =? Lateral area of cylinder = perimeter of bottom circle × height =? 3. 14 x3x 2 x 6.5 = 122.46cm?

Bottom area =3. 14x3? x2 = 56.52cm?

Surface area =122.46+56.52 =178.98cm?

2. 2cm in diameter and 7cm in height. What is the lateral area?

Solution:? Surface area of cylinder S=πDh

≈3 14×7×2

=43.96cm?

3. 100 The surface of the oil drum should be painted, with a weight of 0.6kg per square meter. The bottom of each oil drum has a diameter of 40 cm and a height of 60 cm. 100 How much paint do you need?

Solution: The bottom radius of the oil drum is

40 ÷ 2 = 20cm = 0.2m.

The bottom area of the oil drum is

0.2× 0.2× 3.14 = 0.1256 (m2)

The horizontal area of the oil drum is

0.2× 2× 3. 14× 0.6 = 0.7536 (m2)

The area to be painted of the oil drum is as follows

0.1256× 2+0.7536 =1.0048 (m2)

Brush 100 oil drum for painting.

0.6×1.0048×100 = 60.288 (kg)

4. Make cylindrical ventilation pipes with iron sheets, each with a length of 80cm and a radius of 5cm. How much iron is used in 20 knots?

Solution: The main areas of Section 20 are

5× 2× 3. 14× 80× 20 = 50240 cm2.

iron sheet

5. What is the lateral area of a cylinder with a base diameter of 6cm and a height of 12cm and 100 such cylinders?

Solution:? Lateral area of cylinder = circumference of bottom circle × height = 5.3.14× 6×12×100 = 22,608 square centimeters.

Just press the formula! If you don't understand anything, please consult and hope to adopt it!