Set the original height x, and the drop of 1 meter becomes x- 1.

The point where the ladder intersects the ground, and the distance from the wall is set to y.

Then according to Pythagorean theorem, y is equal to the root sign (square of 25-X ~ ~

After falling 1 m, the distance between the point where the ladder intersects the ground and the wall is

Under the root sign (square of 25 -(X- 1))

That is to say, the distance of horizontal movement is

Under the root sign (square of 25-(X- 1)) minus the root sign (square of 25-X).

If this distance is equal to 1, then solve this equation.

Under the root sign (square of 25 -(x- 1))- under the root sign (square of 25-x) = 1.

Mobile projects,

Under the root number (square of 25 -(x- 1)) = under the root number1+(square of 25-x)

Square on both sides

Square of 25-x +2x-1=1square of+25-x+2 root sign (square of 25-x)

Finishing, 2x-2 = 2 root number (square of 25-x)

That is, x- 1 = root number (square of 25-x)

Square on both sides

Square of x-2x+1= square of 25-x.

2*x-2x-24 squared = 0

The square of x-x- 12 = 0.

X = 4 or x = -3 (s).

The solution is that x is 4. That is to say, only when the height is 4, it will drop 1 m and move horizontally 1 m.

Otherwise it will not move 1 m:)