(1) According to the phenotype and proportion of F 1, male white-winged white eyes: female red-winged red eyes: female white-winged red eyes = 4: 3: 1, all males are white-eyed, and all females are red-eyed, so the gene controlling blinking is located on the X chromosome. The title puts forward that "the wings of male individuals can only be white", which belongs to heredity.

(2) Female middle red wing: white wing = 3: 1, and red wing is dominant, so the parental genotype is Aa×Aa ... And because all males in the offspring are white eyes (XBY) and females are red eyes (XBX-), the female parent is xbxbxbxbb and the male parent is XbY.

(3) In F1generation, the female with white wings and red eyes is aaXBXb, and the male with white wings and white eyes is (1/4AA, 1/2Aa, 1/4aa)XbY. Because the male's wings can only be white, only the red-eye gene should be considered, so the white-winged red-eye male (1/4aa) XBY.

(4) If only the inheritance of wing color is considered, the white-winged individuals of F 1 include all males (1/2) and white-winged females (1/8), accounting for 5/8 of all F 1. Among them, male homozygotes are aa and AA, accounting for 65438 of F 1. White-winged females are all aa, so homozygotes account for = (1/4+1/8) ÷ 5/8 = 3/5.

(5) If polar bodies are produced by the division of secondary oocytes, the genotype of oocytes is also AaXb；; If the polar body is produced by the division of the first polar body, the genotype of the egg cell is XB.

So the answer is:

(1) Often? X

(2)AaXBYAaXbXb

(3) 1/4

(4)3/5

(5)AaXb？ Or XB