Assignment format: let x (which can be replaced by corresponding letters) = value (such as 0, 1,-1, etc.). )
Example: Known (1? X)7=a0+a 1x+a2x (square) +a3x (cubic)+. +a7x7 Power. What is the value of a 1+a3+a5+a7?
Analysis: Because the equation in the title holds for all X, we can make x= 1 and x=- 1 in the known equation, and get A0+A1+A2+A3+A4+A5+A6+A7 = 0, ① respectively.
A0-a1+A2-A3+A4-A5+A6-A7 = (-2) to the 7th power ②
From ① to ②, we get 2(a 1+a3+a5+a7)=-(-2)7, so we get a 1+a3+a5+a7=64.