Question 1: 1. When x- 1 > 0 is x > 1, the original inequality is transformed into: x squared-1 < 1, that is, x squared < 2, and the solution set is 65438. When x- 1 < 0, that is, x < 1, the original inequality is transformed into: x square-1 > 1, that is, x square > 2, and the solution is: x root number 2 (irrelevant, omitted), so x.

2. when x- 1 > 0 represents x > 1, the original inequality group is transformed into: 1-x < 1 and x- 1 > 1, and the solution inequality group is: x > 0, x.

When x- 1 < 0, that is, x < 1, the original inequality group is transformed into: 1-x > 1 and x- 1 < 1, and the solution inequality group is: x < 0, x.

When x= 1 in the two questions, the denominator is zero and meaningless.

Both problems use the basic properties of inequality: when both sides of inequality are multiplied by positive numbers at the same time, the inequality still holds, and the inequality does not change direction; Both sides of the inequality are multiplied by negative numbers at the same time, and the unequal numbers in the inequality have to change directions;