72=8×9

X679y is divisible by both 8 and 9.

Divisible by 8, the last three digits are multiples of 8.

So y=2

Is a multiple of 9, then the sum of digits can be divisible by 9.

6+7+9+2=24

x=27-24=3

The required five digits are: 36792.

2.

9 19 is divisible by 9.

19 19×2÷9=426 ...

19191919 ÷ 9 = 2132435 ...

The unit number of quotient is 5.

3.

19 19 19, three consecutive 19, divisible by 13.

19 19×2÷3= 1279... 1

19÷ 13= 1...6

The remainder is 6.

4.

Number, after adding 2, can be divisible by 5 and 7 at the same time, and the remainder after dividing by 3 is 1.

The least common multiple of 5 and 7 is 35.

The remainder of 35×2=70 divided by 3 is 1

70-2=68 is the minimum number that meets the requirements.

The least common multiple of 3, 5 and 7 is 105.

The minimum three digits that meet the requirements are 68+ 105= 173.

Answer format:

Question 1:

Yes (36792)

Question 2:

A: Yes (5)

Question 3:

A: Yes (6)

Question 4:

A: Yes (173)