1、4^x*32^y=2^2x*2^5y=2^(2x+5y)=2^3=8

2, a x = 5, a (x+y) = 25, a y = a (x+y-x) = a (x+y)/a x = 5, a 5+a y = 5+ 10.

3. The original algebraic expression = x (n+(n-1)+...+2+1) * y (1+2+...+(n-1)+n) = 0.

4、x^(m+n)=x^(m+2n-n)=x^(m+2n)/x^n= 16/2=8

5. (x+1) (x 2-5ax+a) = x 3+(1-5a) x 2-4ax+a is 1-5a=0 because the product does not contain the quadratic power of x.

6. (9a) (n-3) * b2n * (-2a) 3m * b (5-n) = a * a (n-3+3m) * b (5+n) where a is the coefficient.

Then n-3+3m=4, 5+n=9, m= 1, n=4.

7. Is the topic wrong?

M 2+m- 1 = 0, two solutions can be obtained by finding the root formula, and then two results can be obtained by substituting it into the formula.