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Complete works of key topics of mathematics in grade three
Solution: in∶diamond ABCD, AB=2, ∠ C = 60,

△ Abd is an equilateral triangle,

BO=DO= 1,

AO=√ (Addo? )=3

Arc length of the first rotation =(60π×√3)/ 180=(√3)π/3.

∫ Arc length of the first and second coils = (60 π×√ 3)/180+(60 π×√ 3)/180 = (2×√ 3) π/3.

The arc length of the third turn is: (60 π×1)180 = π/3.

If it goes through 3n times (n is a positive integer)

∫3n÷3 = n,

Therefore, after 3n(n is a positive integer) times, the total length of the path that the diamond center O passes through is:

n×[(2√3+ 1)π/3+π/3]=πn(2√3+ 1)/3

3n = 36

So substitute (8√3+4)π.