p 1 = P0 = 1.0× 105 pa；

t 1 = 273+77 = 350k； T2 = 273+42 = 3 15K；

According to Charlie's law p 1t 1 = p2t2.

P2 = t2t 1p 1 = 3 15350× 1.0× 105 pa = 0.9× 105？ protactinium

(2) When the boiled egg slowly falls into the bottle, according to the balance of forces, there are

G+p0S=p2S+f

That is, f = g+(P0-P2) s = [0.50+(1.0×105-0.9×105 )×1.0×/kloc-0-3].

Answer: (1) When the temperature is 42℃, the pressure in the tank becomes 0.9× 105? protactinium

(2) The resistance between the boiled egg and the bottle mouth is 10.5 N when it slowly falls into the bottle.