I forgot what the picture looks like, but I still thought about the general process, which may not be very clear. This problem has been done for a long time. After the circle moves, the arc length corresponding to the central angle is equal to 2, just look at the picture. α=l/r =2/ 1=2. So the radian of the central angle is 2, and then the auxiliary line with the center parallel to the X axis is made, so the degree of the small angle above is (2-π/2), and the abscissa of point P is 2-cos(2-π2), so the abscissa is 2-sin2 and the ordinate is/kloc-. The answer is (2-sin2, 1-cos 2).