The process of proof is as follows: let its diagonal intersect at point O.

According to the meaning of the question, ∠ BAE = α, ∠ OAQ = α, so ∠ BAE=∠OAQ.

Because Pei = OAQ = 90.

So △ Abe △△ AOQ

∴AB/AO=AE/AQ

So AB/AE=AO/AQ, and because ∠ Bao = ∠ EAQ = 45.

So △ Bao △ EAQ

So ∠ AEQ = ∠ ABO = 45.

Therefore, the degree of ∠AEQ remains unchanged.