It is known that in △ABC, be and cf are bisectors of ∠B and ∠C, and be = cf Proof: AB=AC.

As soon as the proof method is set with AB≠AC, it is better to set AB & gtAC, so ∠ ACB >; ∠ABC, so ∠ BCF =∠ FCE =∠ ACB/2 > ∠ ABC/2 =∠ CBE =∠ EBF.

In △BCF and △CBE, because BC=BC, BE=CF, ∠ BCF >; ∠CBE。

So Chief Executive BF>. (1)

As a parallelogram BEGF, then ∠EBF=∠FGC, EG=BF, FG=BE=CF, and even CG.

So △FCG is an isosceles triangle, so ∠FCG=∠FGC.

Because ∠FCE & gt；; ∠FGE, so ∠ ECG