Fixed point problem in line segment

1. The distance between two ships when they leave in 30 minutes is the total distance minus the distance traveled by speedboats and cruise ships, namely:

140-0.5×(67+3)+0.5×(27+3)

=140-35+15 =120 (km).

2. It takes 140/(67+3)=2 (hours) for a speedboat to travel downstream from A to B,

When the speedboat arrives at B, the distance between the cruise ship and B is 2(27+3)=60 (km).

When the speedboat sails from B to A x hours, the distance between the two ships is 100 km.

(67-3)x+(27+3)x+60= 100，

The solution is x=20/47,

During the voyage, two ships need 2+20/47 hours, that is, two 20/47 hours apart 100 km.

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