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Put forward the analysis process of primary school mathematics problems
This is the correct part of a friend of Ben's 1974:

[60÷4= 15]

Divided into 15 segments,

15 ten 1= 16 faces

Insert 16 flag

The least common multiple of 4 and 6 is 12,

60÷ 12=5 faces

Add the first side: 50 1=6 sides without pulling]

The back is wrong, what needs to be pulled out should be:

16-6= 10 (surface)

Note: Because 12 is the least common multiple, that is to say, according to these two insertion methods, there are signs at the multiples of 12 and 12, so it is reserved, including the starting point of * * *. According to 1 2m, it is divided into five sections, and the original two faces of each section should be pulled out, of which 1 face is not needed, and the other1face should be moved and reinserted, and the multiples of 6m and 6 should be inserted instead of just pulling out five faces.