Solution: intersection a is AE⊥l of point e, intersection c is CF⊥AB, and intersection AB extends to point f,

Let AE=x,

∠∠BCD = 120，∠ACB= 15，

∴∠ACE=45，

∴∠BCF=∠ACF-∠ACB=30，

In Rt△ACE, ∫∠ACE = 45,

∴EC=AE=x，

In rt delta ade, ADC = 30,

∴ED=AEcot30 =3x，

Judging from the meaning of the question, 3x-x=20,

Solution: x= 10(3+ 1),

AE=CF= 10(3+ 1) meters can be obtained.

In Rt△ACF, ∫∠ACF = 45,

∴AF=CF= 10(3+ 1) meters,

In Rt△BCF, ∫∠BCF = 30,

∴BF = cftan 30 =( 10+ 1033)m，

So AB = AF-BF = 2033m m.

A: The distance between Pagoda A and Pagoda B is 2033 meters.