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A primary school math problem for help! ! ! ! !
Every migrant worker works one day114/40 =1/560.

It will be 1/560X 40X2= 1/7 after 40 working days.

The remaining 6/7 needs 60 migrant workers to do 6/7/(1/560x60) = 6/7x560/60 = 8.

So 14-2-8= 4 days in advance.

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