Junior one mathematics comprehensive volume volume II

( 1)

First, multiple-choice questions (4 points for each question, ***36 points)

1, (-1)2008 is ()

A. The largest negative number B. The smallest non-negative number

C. The smallest positive integer D. The integer with the smallest absolute value

2. If expressed as an integer, the integer x can be * * * with ().

A.3 B.4 C.5 D.6

3. If |a|=4, |b|=2, and |a+b|=a+b, then the value of a-b can only be ().

A.2B.2C.6D.2 or 6

4, if +x-2 = 0, then the value range of x is ()

A.x>2B.x0(D)

The correct proposition is ()

(A)4 (B)3 (C)2 (D) 1。

5. As shown in Figure 3, among the four artistic terms of "People's Olympics", there are () (a)1(b) 2 (c) 3 (d) four axisymmetric figures.

6. It is known that p, q, r and s are mutually different positive integers, and they satisfy, then ()

(A)(B)(C)(D)

7. Teacher Han specially made four identical cubes and placed them as shown in Figure 4(a) and Figure 4(b) respectively. Then the sum of the points of the four bottom squares in Figure 4(b) is () (a)11(b)13 (c) 65438.

8. As shown in Figure 5, if AB//CD, the relationship between ∠B, ∠C and ∠E is () (A)∠B+∠C+∠E= 180? (B)∠B+∠E-∠C= 180？

(C)∠B+∠C-∠E= 180？ (D)∠C+∠E-∠B= 180？

9. Equation 2007x+2007a+2008a with X as unknown number = 0 (A, B is rational number, B >；; 0) has a positive integer solution, then ab is ()

(a) Negative numbers (b) Non-negative numbers (c) Positive numbers (d) Zero

10. Define a new operation for any four rational numbers A, B, C and D: =ad-bc, and if it is known = 18, then x= ().

(A)- 1(B)2(C)3(D)4

Two. Group A fills in the blanks (4 points for each small question, ***40 points)

1 1. Xiaoming played 20 games and 95% won. If he doesn't lose the next game, the winning rate is 96%. Xiaoming needs to play another game.

12. As shown in Figure 6, point D is on BC, at right angles to Rt△ABC, BD=2, DC=3. If AB=m and AD=n, then

=。 13.averagenumberofp, q, ris4, and averagenumberofp, q, r, xis5, then x=.

(English dictionary: averagenumber average)

14. Calculation: =

15. If and are opposite numbers, then =.

16. As shown in Figure 7, the square ABCD has an area of 25 square centimeters, with point E on AB, BE= 1.5AE, point F on BC, and BE=4CF, so the distance from point D to EF is square centimeters. 17. If three rational numbers A, B and C satisfy A: B: C = 2: 3: 5, then a+b+c=.

18. A male and a female athlete practice long-distance running on the circular track. Male athletes are faster than female athletes. If they start from the same starting point in the opposite direction at the same time, they meet every 25 minutes. Now they are starting from the same starting point and heading in the same direction at the same time. The male athlete caught up with the female athlete after 15 minutes, running more laps than the female athlete 16.

19. Given that m, n and p are integers, then =.

20. If known, then =

Three. Fill in the blanks in group B (8 points for each small question, 49 points for * * *, two spaces for each question, 4 points for each space)

2 1. At present, there is brine 100 kg, containing brine 15%. To increase the salt content of this brine by 5%, it is necessary to add 10 kg of pure salt; To reduce the salt content of this brine by 5%, it is necessary to add kilograms of water.

22. After Liu Xiang, a famous track and field athlete in China, set a new world record of 1 10 meter hurdle, the expert group input the images and data of Liu Xiang's previous competitions and trainings into the computer and analyzed them, showing that each "hurdle period" (the time taken to cross two adjacent hurdles) when he crossed 10 hurdle (the distance between two adjacent hurdles was equal) was as follows. The distance from the last column to the finish line is 14.02 meters, and Liu Xiang's best performance in this section is 1.4 seconds. According to the above data, the distance between two adjacent columns is seconds. Theoretically, the best performance of Liu Xiang 1 100 meter hurdles can reach seconds.

23. A poet praised the water of Lijiang River in this way: how deep love is, how beautiful dreams are. /If love is like a dream, the water of Lijiang River. In the translated and published poetry anthology, the English translation of this passage is: "DeepasFeeling and Sweet Remas/The Lijiang Riverruns". Please count the number of English letters in this English poem (26). The English letters that appear the least are; The English letter with the highest frequency is.

24. If, then = =.

25. Fold a thin iron with a length of 25 cm into a triangle with prime sides (unit: cm). If the three sides of such a triangle are a, b, c, and a≤b≤c, then (a, b, c) has a set of solutions, and all the triangles formed are triangles. Answers to the 18th "Hope Cup" National Mathematics Invitational Tournament (Grade One)

First, multiple-choice questions:

Title 123456789 10

Answer BADBCCDBAC

Hint: 2,90

3. If the nth prime number is 47, then n = _ _ _ .2, 3, 5, 7, 1 1, 13, 17, 19, 23, 29, 3655.

7. From (a):1-5,2-4,3-6, so 1+3+6+6= 16.

8. If e is taken as EG//AB, we can get: ∠ b+∠ e-∠ c = 180.

9. To solve the equation, x= is a positive integer, so-2007a-2008b >; 0, because b>0, so A.

Two. Group a fills in the blanks

Prompt: 1 1, assuming that the x field is still needed, you get 20×95%+X =(20+X)×96%:X = 5.

Pythagorean theorem: m2 = bc2+ac2 = 52+ac2n2 = dc2+ac2 = 32+ac2 Available: m2-n2= 16.

13, the average value of p, q and r is 4, the average value of p, q, r and x is 5, and x=?

P+q+r=4×3= 12, p+q+r+x=5×4=20, so x=8.

14, original formula = = =

15、- 1

16, even number DE, DF, from known AB=BC=CD=DA=5, AE=2, BE=3, BF=4, CF= 1, EF=5, s △ def =11.

17, let a = 2k, b = 3k and c = 5k substitute to get k=, so a+b+c= 10k=

18, assuming that the female athlete ran x laps, then the male athlete ran x+ 16 laps.

Then:

Solution: x= 10

19, from the meaning of the question: m=n+ 1, p=m or m=n, p=m+ 1, when m=n+ 1, p=m, the original formula = 3; When m = n and p = m+ 1, the original formula =3. So the original formula =3.

20. The original formula = 3a6+12a4-(a3+2a)+12a2-4.

=3a6+ 12a4+ 12a2-2

=3a3(a3+2a+2a)+ 12a2-2

=3(-2a-2)(-2+2a)+ 12a2-2

= 12- 12 a2+ 12 a2-2

= 10

Third, fill in the blanks in group B.

Tip:

Solutions of 2 1 and 6.2550

22、( 1 10- 13.72- 14.02)÷( 10- 1)=9. 14

2.5+0.96×9+ 1.4= 12.54

23、8;