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The math problem of the person sitting at the table
The point is, if you add 1 to the total number of people, then this number can be divisible by 3, 5, 7 and 9, and the remainder is 1 1.

So first find the least common multiple of 3, 5, 7 and 9.

5*7*9=3 15

Then there was no good way to die, so I began to set the total number of people to 3 15n- 1.

Because 1 1*28=308.

3 15n- 1 =(308+7)n- 1 = 308n+7n- 1

Because 308n is divisible by 1 1, 7n- 1 is required to be divisible by1.

When n=8, 7n- 1=55 is divisible by 1 1.

So the total number of people is 315 * 8-1= 2520-1= 2519.

If the number of people is unlimited, just add 8 to 1 1 at a time.

The total population is 3 1 5 * (8+11n)-1(n = 0,1,2, 3, 4 ...).