From p(c)=0, we know? xp(x) = 0

At this time? Xp(x) → q(a) is true.

When x=b, q(x)=q(b)= 1.

Obviously at this time? Xp(x) → q(b) is true.

When x=c, q(x)=q(c)=0

From p(c)=0, we know? xp(x) = 0

At this time? Xp(x) → q(c) is true.

To sum up, the proposition is always true.