Urgent! Dear mathematicians and gifted scholars, please help me solve the following review questions of sixth grade mathematics in primary school.

1. If the distance between Party A and Party B is X kilometers, then

65+( 1/4)* X =( 1/2)* X+ 10

Solution: x = 220km.

2. Let Party A and Party B be x kilometers apart. rule

[(X/2)-36]/[(X/2)+36]=4/6

Solution: X=360 km

Note: this question grasps that the distance traveled at the same time is directly proportional to the speed, and the speed traveled at the same distance is inversely proportional to the time, so this kind of question can be answered well.

This question is quite similar to the second one. You can do it yourself. Answer: The distance between A and B is1800km.

4. After 8 hours, it will take 4 hours for the bus to continue driving to the second place, so it can be concluded that the section of the truck can be completed within 4 hours, so when the truck and the bus meet, the speed of the two cars is proportional to the distance, and the speed of the bus is twice that of the truck, so the distance between Party A and Party B is 8*(35+35*2)=840 kilometers.

5. Solution: Suppose the speed of the bus is X km/h, then

X/(X-30)=3/2

X = 90km/h

6. When the two cars meet for the second time, the driving time is the same, so the driving distance at the same time is directly proportional to the speed.

Solution: Let AB be x kilometers apart, then

(2X- 130)/(X+ 130)= 3/2

X=650 km

7. For the same distance, the speed of a car is inversely proportional to time.

Solution: Suppose the planned speed of the car is x km/h, then

X/(X- 10)=[ 1+( 1/5)]/ 1

X=60 km/h

Assuming that the planned driving time of the car is y hours, then

Y/(Y-2)=[ 1+( 1/4)]/ 1

Y= 10 hour,

Then the distance between Party A and Party B is 60* 10=600 kilometers.

8. If the distance between two towns is X kilometers, then

[(2/5)* X]/9.6 = 1/[ 1-(3/ 1 1)]

X=33 kilometers

9. Suppose A reaches the midpoint D and B is at position C, then the distance between the two positions of CD is 60 kilometers. Assuming that B accelerates at position C, where is B when A reaches B? The walking time of Party B before and after the speed increase is the same as that of Party A, but before the speed increase of Party B, the speed ratio of Party A to Party B is 5:4. Then, after Party B increases the speed by 50%, the speed ratio of the average speed of Party A and Party B in the same two cycles is 1: 1. It can be concluded that if Party B accelerates at position C, both cars will arrive at position B at the same time. The actual B accelerates at the D position, so when the actual A reaches the B position, B does not reach the B position.

Suppose that when a car arrives at B, B is still X kilometers away from B, then

60/(60+X)=4/(4* 1.5)

X=30 kilometers

10, because a arrives at B and B at a distance of A 10 km, and the departure time of the two cars is the same. The speed ratio of Party A and Party B before the meeting is 5:4, and the speed of Party A from the meeting place to the meeting place has dropped by 20%, so the speed of Party A and Party B after the meeting is the same as that of Party B from the meeting place, and the same distance and speed are the same, so it takes the same amount of time. They spend the same time, so it takes B as much time to get from the meeting place to the place A 10 km as it takes A to get to the meeting place, and the first equation can be obtained. Similarly, time and speed are proportional to distance. You can find out the distance A walked before they met. A and B walked at the same time before they met, so the distance is proportional to the speed and the total distance is obtained.

Suppose that when two cars meet, the distance A walks is X kilometers, then

5/(4* 1.2)=X/(X- 10)

X = 250km km

So the distance between AB and AB is 250/[5/(4+5)] = 450km.

1 1. Suppose there is still X kilometers between A and A when B arrives at B, then

(X+ 100+60)/[X+( 100+60)* 2]= 3/5

X=80 kilometers

12, assuming that the speed of b is X km/h, then

(5/6)/(5/8)=80/X

X=60 km/h

So the distance between the two places is 60* 10=600 kilometers.

13, let the distance between AB and AB be x kilometers, then