AB distance10000m. A rides a bike and B walks. At the same time, from A to B, the speed of A is four times that of B, and A was delayed for a while on the way. B is here. B, A is 200 meters away. How many meters did B walk during the delay?

Solution: The speed ratio of A and B is 4: 1.

Then the distance ratio between Party A and Party B is 4: 1.

So A left 10000-200=9800 meters.

Then B should walk 9800/4=2450 meters.

Because B arrived at B at this time, B left 10000-2450=7550 meters when A lost time.