Fangfang has more lucky money than Honghong 18 yuan. If the red lucky money is more 4 yuan than Fangfang's, how much will Fangfang spend on red 20?
There are a lot of RMB of 50 cents, | cents and | yuan in the red savings box. She wants to withdraw 2 yuan money from it. Rmb has 1 min * 20 = different types of 2 yuan.
1 yuan *2 =2 yuan.
50 points *4 =2 yuan.
Fifty cents *2+1 yuan * 1 =2 yuan.
1 yuan * 1 Zhang+1 angle * 10 Zhang =2 yuan.
1 corner *5 +5 *3
1 corner * 10 +5 corner *2.
1 angle * 15 +5 angle * 1.
Fangfang has more lucky money than Honghong 18 yuan. If Honghong's lucky money is more 4 yuan than Fangfang's, how much will Fangfang give Honghong? The third grade of primary school 18÷2=9 (yuan) 4÷2=2 (yuan) 9+2= 1 1 (yuan)
Fangfang has more lucky money than Honghong 18 yuan. How much does Fangfang have to pay for Honghong's lucky money to be more than Fangfang's, 4 yuan? I hope to explain 1 1 yuan in detail.
There are two from 50 yuan, four from 20 yuan and four RMB 10. Now I want to spend 100 on clothes. There are several payment methods that are easy to calculate. The scheme is 1, and all three denominations are selected. There are two results, 50x 1+20x 1+65438. By analogy, only two denominations are selected, obviously there are only two schemes, 20X4+ 10X2 and 20X3+ 10X4, and only 1 denomination, 50X2, and only five schemes are selected.
The red ones are from 5 yuan and 2 yuan. She wants to take out 47 yuan. How many different formulas are there? 9 RMB from 5 yuan and 1 RMB from 2 yuan.
Seven for five yuan and six for two yuan.
Five tickets for 5 yuan and 1 1 tickets for 2 yuan.
3 tickets for 5 yuan, 16 tickets for 2 yuan.
1 5 yuan and 2 1 2 yuan.
Because 47 is odd, the number of sheets in 5 yuan should be odd, so the maximum number of sheets in 5 yuan is 9, and that in 2 yuan can be determined.
Uncle Zhang has 10 yuan and several RMB bills from 5 yuan. He wants to withdraw 50 yuan money from it. There are _ _ _ _ different methods (1), 5 yuan 10, 5× 10=50 (yuan).
(2)5 yuan's 8, 10 yuan 1, 5×8+ 10=50 (yuan).
(3)5 yuan 6, 10 yuan 2,5× 6+10× 2 = 50 (yuan).
(4)5 yuan 4, 10 yuan 3,5× 4+10× 3 = 50 (yuan).
(5)5 yuan 2, 10 yuan 4,5× 2+10× 4 = 50 (yuan).
(6) 5 10 yuan, 10×5=50 yuan.
A: There are six different grips.
So the answer is: 6.
Li Ming got the same amount of 5 yuan and 1 yuan for the Spring Festival lucky money. 5 yuan and 1 yuan, how much lucky money does Li Ming have? Solution: Because Xiao Ming took five yuan, the number of sheets was the same as that before one yuan.
5+ 1=6,
So the total amount of money Xiao Ming got was an integer multiple of 6.
And options b, c and d are not multiples of 6.
Option a, 48÷6=8,
Therefore, Li Ming may have 48 yuan;
So choose: a.
Take out 50 yuan from three 20 yuan, four 10 yuan, five 5 yuan and eight 1 yuan. 3. There are more than three ways to hold China law, such as:
20+20+ 10
20+20+5*2
20+20+5+ 1*5
20+ 10*3
20+ 10*2+5*2
.....
10*5
10*2+5*5+ 1*5