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Interesting mathematical simplification problem
First of all, tell the landlord a method of square sum cube, that is, hold down Alt, and then press 178 on the keypad, which is a square, and press 179, which is a cube.

Ok, let's begin to answer the question:

I. Fraction reduction

1.(a-b)/(b-a)

∫a-b =-(b-a),

∴ Original formula =- 1

2.(a? +2ab)/(a? b+2ab? )

Original formula =(a? +2ab)/[b? (a? +2ab)]

= 1/b

The landlord should have typed the denominator of this question wrong.

(a? -4ab? )/(a? -4a? b+4ab? )

Original formula =a(a+2b)(a-2b)/a(a-2b)?

=(a+2b)/a-2b

2. General division of fractions

In view of the trouble of typing here, I'll just say the method.

1. Multiply the numerator and denominator of the previous formula by 2x? After multiplying the numerator denominator by 5.

2. The numerator and denominator of the previous formula are all multiplied by 6z? The numerator and denominator of the second formula are multiplied by 4x? Y, the numerator and denominator of the latter formula are all multiplied by 3x? yz

3. The numerator and denominator of the former formula are multiplied by (a+b), and the numerator and denominator of the latter formula are multiplied by (a-b).

4. The former numerator and denominator are multiplied by each other (m? -Huh? ), the numerator and denominator of the latter formula are multiplied by (m+n)

5. Multiply the denominator of the previous formula by 3(x- 1) and the denominator of the latter formula by 2.

By the way, (1-x)? =(x- 1? )

6. The numerator and denominator of the former formula are multiplied by (x+ 1), and the numerator and denominator of the latter formula are multiplied by X..