f(t)=(t+ 1)^2=t^2+2t+ 1

f(x)=x^2+2x+ 1

Several places: 1.f(x+ 1), f(t) and f(x) are all F. We can think that their corresponding relations are the same, but the substituted values are different.

2. Unless otherwise specified, the domains of f (t) and f(x) are both considered as r, and the corresponding relationship is the same, so they are equivalent functions, but the letters are different.

2. Let 2x+ 1= radical number 2, then x= 1/2 (radical number 2- 1).

F (radical number 2)=[ 1/2 (radical number 2- 1)] 2-2 * 1/2 (radical number 2- 1)

= 7/4-3/2 times of the root number 2

I'm also a freshman ~ ~ I just made it ~ ~ I hope it helps ~ ~ Hehe ~ ~