1, from | A | =-A, | B | = B, | C | =-C, | D | =-D, a, c and d are negative, and b is positive, so b is the largest.

| a | > |b| >| c | >； | d | Among the known negative numbers A, C and D, A is the smallest and D is the largest, so the arrangement of the four numbers is: A < C < D < B.

2. Pull 1 time becomes 2, which is 2 1.

Pull twice to become four, which is 2 2.

Pull it three times and it becomes eight, which is 2 3.

Pull it four times and it becomes 16, which is 2 4.

...

So after being pulled seven times, it becomes 128, which is 2 7.

3. The temperature difference between the foot of the mountain and the top of the mountain is 4-(-2) = 6℃

So the height of the mountain peak is: 6 ÷ 0.6×100 =1000 m.

4. Because the values of | x-2 | and | y- 1 | are non-negative no matter how much x and y are equal, only | x-2 |+| y- 1 | = 0 can be established.

5. Divide these numbers 100 into 50 groups:

[(- 1)+2]+[(-3)+4]+{(-5)+6]+...+[(-99)+ 100]=50

6. If the conditions are insufficient, we can only get | c | =-c, | c+b | =-c-c, | a-c | = a-c.

Because the symbols of A and B are different, but we don't know the absolute values of A and B, so | B+A | can't judge how much it is equal, so we can only discuss it in different situations:

If a

The original formula =-C-(-C-B)+A-C+(-B-A) =-C+C+B+A-C-B-A =-C.

If a =-b, then b+a = 0, so:

The original formula =-c-(-c-b)+a-c+0 = b+a-c.

If a >-b, there is b+a > 0, so:

The original formula =-C-(-C-B)+A-C+(B+A) =-C+C+B+A-C+B+A = 2A+2B-C.

7. Grouping is similar to question 5. Four adjacent groups are divided into one group, and the sum of each group is -4. A * * * has 502 groups, so the result is (-4) × 502 =-2008.

8. Known: A =-5/3, B =-2/5.

So the original formula = [-5/3+3× (-2/5)]/[-5/3-2× (-2/5)] = 43/13.

9. The number of squares equal to a cube is (1,-1, 0), and the number of cubes equal to -8 is (-2).

10, if 1 ≤ AB < 10, there is: AB = C, so there is m+n = p.

If 10 ≤ AB < 100, then: AB = 10c, then: m+n+1= p.