or

( 1)

∴a(- 1,0)b(3,0)； ( 1)

Substitute it into point c, and the abscissa x=2.

Y=-3, ∴C(2, -3)( 1) is obtained.

The resolution function of straight line AC is y=-x- 1.

(2) The abscissa of point P is x(- 1≤x≤2) (Note: if the range of X is not written, no penalty will be deducted).

Then the coordinates of p and e are: P(x, -x- 1) and (1) respectively.

Electrons (

( 1)

Point ∵P is above point E, and PE=

(2 points)

Suffer from hell

Maximum value of PE =

( 1)

(3) There are four such points f, namely