Junior high school mathematical geometry problem ABCD square, P is a moving point on the X axis, and the connection DP is a vertical line ... when △PED is an isosceles right triangle?

Existence, from the title, when DP=PE, △DPE is an isosceles right triangle, at this time △ APD △ OEP, so OP=AD=4.

So the P coordinate (-4,0) or (4,0) corresponds to the E coordinate (0, 1), (0,7).

Next, find the intersection of DE and X axis when finding the area (-4,0), and the intersection of DE and X axis and DP and BC when finding the triangle area (4,0), and then subtract the two triangle areas from the square area. . You should be able to find it easily by drawing a picture.

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