According to the analysis data, the current is I=0.3A, U=IR and P=UI, so P=I2R.

That is, when the current flowing through the resistor R 1 is 0.3A, the electric power consumed by R 1 is P=(0.3A)2R 1,

So the answer is: when the current through the resistor R 1 is 0.3A, the electric power consumed by R 1 is p = (0.3a) 2r 1.