Current location - Training Enrollment Network - Mathematics courses - Distance problem in junior one mathematics problem
Distance problem in junior one mathematics problem
Scheme 1. Xiaoming's father took Xiaoming to the cinema by motorcycle, and Xiaogang started running at the same time. It takes Xiao Ming's time.

T 1=3*60/40=4.5 minutes.

Then Xiao Ming's father went back to see Xiao Gang, and the time when they met was t2=6*60/( 10+40)=7.2.

Minutes, the time from the assembly point to the cinema T3 = (3-7.2 *10/60)/40 * 60 = 2.7.

minute

So the total time for Xiaogang to arrive at the cinema is t=7.2+2.7=9.9 minutes. He won't be late.

Scheme 2: It takes t 1=3*60/40=4.5 minutes for Xiaoming's father to take Xiaoming to the cinema.

At this time, let Xiaogang wait for Xiao Ming's father to pick him up. The total time required to reach the cinema is:

T2 = t1+6 * 60/40 =13.5 minutes won't be late.