The distance of car B is proportional to time, and car B moves in a straight line at a constant speed. As can be seen from the figure, the speed of car B is VB = SBT B =105s = 2m/s;

In the fifth second, the distance traveled by car B is s=v, and car B is T = 2m/s×1s = 2m;

(2) Car A is stationary, the speed of car B is 2m/s, with parking space B as the reference, the position of car A relative to car B is constantly changing, and car A is moving.

So, the answer is: 2; 2; Exercise.