Answer: I appreciate the solution of (1) Zhong C best.

Solve the equations x+y=2①, 2x+3y=6②.

2x+2y=4③ comes from ①×2.

From ②-③: y=2, substitute y=2 into ①: x=0.

Substituting x = 0 and y = 2 into 3x+2y=7k-2, we get 0+4 = 7k-2, and k = 6/7.

This solution can first find the values of x and y, and then substitute it into the equation containing k to get the value of k, which avoids the other two methods of solving the unknowns of x and y, and the method used by C is simpler and clearer.

26. According to the meaning of the question, the team with more wins will qualify. Assuming that the Gaoshan team wins the last five games, the Hai team must win at least X games to qualify.

14+x & gt； 12+5x & gt； three

Therefore, the sea team must win at least four games to ensure the qualifying.

In the next game, the Hai team beat the Gaoshan team by at least 4 points, which means that the Hai team won the game. Assuming that the Gaoshan team wins the other four games, the Hai team must win at least Y games to qualify.

14+ 1+y & gt； 12+4 y > 1

Therefore, the Ocean team must win at least two games to ensure the qualification.