20(30-x)= 2.5
x=22
2. Set the correspondent to catch up with the student team of the class (1) in x minutes.
75(20+x)=225x
x = 1
3、72*4/(4-0.4)=80 km/h。
4. Suppose that the car passes the bus 13.6km after driving for x hours.
108 X- 13.6 = 92 *(X+0.2)
108 x- 13.6 = 92X+ 18.4
108 x-92X = 13.6+ 18.4
16X=32
X=2
5. Set X to catch up.
Then 170x-70x=70*5.
Solution x=3.5 minutes.
6. Meeting time =2300×2÷( 150+80)=20 minutes.
Sister, please: 20×80= 1600 meters.
7. Suppose my mother walks home from work for x minutes today, which usually takes X+4 minutes.
70X=60(X+4)
70X-60X=240
10X=240
X=24
8. Set up the car and drive for x hours before catching the bus.
1 10X=88*(X+0.3)
1 10X=88X+26.4
22X=26.4
X= 1.2
It took 1.2 hours to catch the bus.
Hope to adopt, I'm exhausted.
Difficulties: How to determine the point M? Because the side lengths of the left right-angled triangle are 3, 4 and 5 respectivel