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A quick solution to a parallelogram geometry problem in junior high school mathematics
AD = BC and AD∨BC, AM=AD/2, CN=BC/2.

∴AM=CN and am∨cn

∴ Quadrilateral ANCM is a parallelogram

∴AN∥CM

Similarly, BM sigma dn

∴ Quadrilateral PNQM is a parallelogram

∫AM = AD/2 = 2AB/2 = AB,AD∨BC。

∴∠ 1=∠2,∠ 1=∠3

∴∠2=∠3

And AB=BN,

∴BP vertical safety,

That is, ∠NPM is a right angle,

So the parallelogram PNQM is a rectangle.