2. Original formula = llime x = 1
3、y=x^x
=e^[ln(x^x)]
=e^(xlnx)
Let u=xlnx, then y = e u.
y'=(x^u)'? hello
=(e^u)? ' xlnx '
=[e^(xlnx)]? [x'lnx+x(lnx)']
=[e^(xlnx)]? (lnx+x? 1/x)
=(x^x)( 1+lnx)