23 25 27

24 29 22

Problem-solving instruction: first calculate the given number: 25X5= 125.

Let's see how many eights there are in 75***, and their sum should be: 75X8=600.

Among them, the number used twice is 4, the number used three times is 4, and the number used four times is 1, which must be a multiple of 25. So the number used four times in the middle must be 25, and the rest must be a pair combination, as long as the sum of the two numbers is a multiple of 50.