(1) According to when 0≤x≤25, the distance from the freight car H to A, B and C is obtained by combining images, and then the functional relationship between Y and X is obtained. Then, when 25 ≤ x ≤ 35, calculate the distances from H to A, B and C respectively, and Y = 100 can be obtained.

(2) Using the value range of x obtained in (1), the function image of y and x and the image of straight line y = 100 are obtained;

(3) Combined with the image, we can get the position of the truck when it travels the shortest distance every day.

Answer:

Solution:

(1)∵ When 0≤x≤25,

The round trip distance of the truck from H to A is 2x,

1 round trip distance from h to b is: 2 (5+25-x) = 60-2x,

The round-trip distance from H to C is 4 (25 ﹣ x+10) =140 ﹣ 4x.

The daily distance traveled by this truck is: y = 60 ~ 2x+2x+140 ~ 4x = ~ 4x+200.

When 25 < x ≤ 35,

The round trip distance of the truck from H to A is 2x,

The round-trip distance from H to B is 1 time: 2 (5+x-25) = 2x-40,

The two round-trip distance between H and C is: 4 [10 ﹣ (x ﹣ 25)] =140 ﹣ 4x,

Therefore, the daily distance traveled by this truck is: y = 2x+2x-40+140-4x =100;

So the answer is: 60 ~ 2x, 140 ~ 4x, ~-4x+200,100;

(2) According to when 0≤x≤25, y =-4x+200,

x=0，y=200，x=25，y= 100，

When 25 < x ≤ 35, y =100;

As shown in the figure:

(3) According to the image of (2):

When 25≤x≤35, y is always equal to 100 km, at which time the value of y is the smallest, and it is concluded that the CD section of distribution center H is completed, and the shortest distance that this truck travels every day is 100km.