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A very difficult fifth-grade math problem
1, according to the meaning of the question: these five numbers are redundant about 3. The smallest number can be 1, so the rest is: 4,7, 10, 13. So the total is:1+4+7+10+13 = 35.

In addition, according to the new mathematical system, 0 is also a natural number, so it can be considered as: 0+3+6+9+ 12 = 30.

2. According to the meaning of the question, each pile of candy is congruent with 3, the remainder is 2, and the parity is the same, so it is obviously odd, and the congruence with 4 is 1. Because the total number is the largest. Let's look at the list of prime numbers within 100: 2, 3, 5, 7,1,13, 17, 19, 23, 29, 3/kloc.

Eligible ones are: 5, 17, 29, 4 1 89. * * * There are five, so the number of piles is five, and the total number of candy bars is:

5+ 17+29+4 1+89= 18 1

2.

17 is divided by 3, so the number of each heap is a multiple of 3 plus 2;

Any four piles of candy are multiples of four, so the parity of each pile is the same. So every pile is odd.

The largest prime number in 100 is 97,97 = 5+5+17+29+41.

Each addend is a multiple of 3 plus 2.

So 97 at most. 5、5、 17、29、4 1