(1) On the image, Mr. Guo's departure time is 0: 00, and Mr. Tang's departure time is -5, that is, it took Mr. Tang 25+5=30 minutes to finish the 24km race, so Mr. Tang's speed is 24/25 = 0.96km/min, and the time for Mr. Guo to arrive at the flower shop is 10 minute.

(2) Miss Tang: y=0.96(x+5)

x≤25

Let Miss Guo start with speed v, then10 v+(25-15) (v-0.6) = 24.

V =1.5km/min

Teacher Guo:

y= 1.5x

0≤x≤ 10

y= 15

10≤x≤ 15

y= 15+0.9(x- 15)

15≤x≤25

(2) When Mr. Guo was 4.5km away from Mr. Luo's home, he walked 24-4.5 =19.5 (km) >15.

∴ 19.5= 15+0.9(x- 15)

X=20 (minutes)

Teacher Tang walked 20×0.96= 19.2 (km).

The distance to Teacher Luo's home is 24- 19.2=4.8 (km).