First, by definition. Get F(x)=sin2x-cos2x=√2sin(2x-π/4).

Then if f(x) wants to move to the right, it will move above the original function according to the law of left+right-.

Become:

=√2 sin(2(x-π/3)-π/4)= 2 sin(2x- 1 1π/ 12)

The period is T=2π/w=π.

Let 2x-11π/12 = π/2+kπ.

X = 17π/24+kπ/2。

But I don't know why C doesn't hold. The following friends and I have the same calculation.

This should be a wrong question. I asked my three classmates to do the math and said there was no answer.