0.45%, the probability of another person getting two aces is 2/50/49=0.08%.
So:
0.45%*0.08%*(6*5
/2) (possibility of randomly selecting two people from six people) = 1
About one in ten thousand.
Between 0.54 and 0.57.
1, as shown in the figure: because HD¡ÍBC and HF¡ÍAB, H, F, B and D are four * * * cycles.
Then ¡ÏDFH=¡ÏDBH, and the sam