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Mathematical problems in purchasing prizes
First prize football 40*3= 120

Second prize pen 22*4=88.

Third prize notebook 12*6=72

Fourth Prize Eraser 12*4=48

120+88+72+48=328, leaving 22, didn't say it would be spent?

Of course, you can also talk about replacing the first prize football with a tennis racket, which can save 15 yuan.

The third prize was replaced by a badminton racket, which cost 6*6=36 more.

So 22+ 15-36= 1, leaving 1 yuan.