∴AO=n.QO=n

And AB=2,

∴B(-n+2,0)

∴ 1/2m=-n+2

The solution is m=-2n+4.

Solution y=x+n

y=-2x+(-2n+4)

X=-n+4/3。

y=4/3

Let PC⊥x axis be on the C axis and ⊥y axis be on the D axis.

∴PD=-n+4/3

PC=4/3

∴S△APB= 1/2 personal computer company

=4/3

The area PQOB of the quadrilateral is 5/6.

∴S△AQO=S△APB-S quadrilateral PQOB

= 1/2

And s △ aqo = 1/2 ao qo.

= 1/2n？

∴ 1/2= 1/2n？ .

The solution is n= 1.

∴P( 1/3,4/3)

PA:y=x+ 1。

PB: y=-2x+2。