This question is very interesting. Firstly, it is simplified as ax-x+ay+2y+5-2a=0.

∴a(x+y-2)+2y-x+5=0

If any value of a in the equation holds, then a(x+y-2)=0 can be analyzed.

So x+y=2.

So the equation 2y-x+5=0 is obtained as follows.

∴x=2y+5

Y=- 1。

x=3

It is verified that no matter what value A takes, the above values of X and Y can make the equation hold (note: the value of A is not equal to 1 and -2).