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Classical solution of junior high school mathematics
(1) If a-b =-3b, find the value of a to the third power× b to the 27th power.

From a-b =-3b, a+3b=b,

A power of 3× b power of 27 = (3a )× (33) b = (3a )× (33b) = 3 (a+3b) = 3b3b is the b power of 3.

(2) Given that the m power of 10 =4 and the n power of 10 =5, find the 3m+2n power of 10.

The 3m+2n power of 10 =10 (3m )×10 (2n) = (10m) 3x (10n) 2 = (4 3 )× (.

(3) It is known that the m power of 3× 9× the m power of 27 = 16, and the value of m is found. ..

The m power of 3× 9× the m power of 27 = 3× 3 (2m )× 3 (3m) = 3 (1+2m+3m) = 3 (1+5m) = 316.

So 1+5m= 16, the solution is m=3.

(4) Simplify and evaluate A? ×(-b? )? +(negative 1/2ab? )? , where a= 1/4 and b=4.

Answer? ×(-b? )? +(negative 1/2ab? )? =a? ×b^6+(- 1/8)a? b^6

=(7/8)a? b^6

When a= 1/4 and b=4, the original formula =(7/8)×(ab)? b?

=(7/8)×[( 1/4)×4]×4?

=(7/8)×4?

=56