The first solution can set the required area as x, the square as y and the sector as z, and the formula is 2z-y = x.2z = 2× 2× 3.14 (two-digit approximation of π) ÷4×2=6.28. 6.28-y=z, y=2×2=4 .x=6.28-4=2.28. The first one is completely correct.

You haven't written the second solution yet. what am I supposed to do？ However, as long as you write it, I will try my best to help you, even though I am only a primary school student.