1, if there is no small solid block to use, the thin line is not applicable. Please note that the error of thin line labeling is too large.
Beakers need two identical ones.
3. Without a measuring cylinder, you need a scale.
Operating steps:
1, put two beakers into the left and right plates of the balance respectively, and adjust the balance;
2. Add proper amount of water and milk into the two beakers respectively until the balance is restored;
3. Measure the depth of water and milk (H water, H milk) in the beaker with a scale;
4. Organize the equipment.
Data processing:
1, indicating the quality of water and milk respectively: m water = ρ water v water = ρ water Sh water, m milk = ρ milk v milk = ρ milk Sh milk;
Because the balance is balanced twice, the quality of water and milk is equal, so there is
ρ milk Sh milk = ρ water Sh water,
Get: ρ milk = ρ water h water /h milk,
Other methods:
Equipment: an elastic dynamometer, an iron block, a thread, a glass of water and a glass of milk. It is required to design an experiment to measure the density of milk and write a mathematical expression.
Experimental steps:
1, hang the iron block on the spring dynamometer with fine iron wire, and measure the gravity of the iron block in the air (G0);
2. Measure the gravity indicator (G') after the iron block is "submerged" in the water;
3. Measure the gravity indicator (G'') after the iron block is "immersed" in the milk.
Data processing:
1, the liquid volume displaced by the iron block is obtained from the f float' = ρ water gV row =F float'/(ρ water G):
V row =F floating'/(ρ water g)=(G0-G')/(ρ water g);
2. Obtain ρ milk =F float''/gV row from F float' = ρ milk GV row to find the density of milk:
ρ milk = f float''/gvrow = (G0-g'')/[g (G0-g')/(ρ water G)] = [(G0-G') ρ water ]/(G0-G').