(1) in Rt△OMH, ∠ ohm = 90, OM = 25, MH = OM× SINα = 15, so OH = 20, MB = HA = 25-20 = 5 (cm), so the height of the hoop hook from the ground is
(2)
∠∠ home +∠OMH=∠OMH+∠FMN=90, ∠FMN =∠ home = α,
∴ FN/FM=sinα=3/5
That is, fn = 3/5 FM. In Rt△FMN, ∠ FNM = 90, Mn = BC = AC-AB = 55- 15 = 40 (cm), and FM square = FN square +MN square is defined by Pythagorean theorem, that is, FM square = (3/5 FM) square.